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15 October, 21:30

Find the value of "y" log (4y+1) = log (y-7) - 2log2

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  1. 15 October, 21:58
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    y = - 8/15

    Step-by-step explanation:

    log (4y + 1) = log (y - 7) - 2log2

    log (4y + 1) = log (y - 7) - log2² (power law)

    log (4y + 1) = log [ (y - 7) / 4]

    4y + 1 = (y - 7) / 4 (remove log)

    4 (4y + 1) = y - 7

    16y - y = - 8

    15y = - 8

    y = - 8/15
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