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16 April, 21:35

B2-4b+4=0 using quadratic forumla

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  1. 16 April, 21:38
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    Trying to factor by splitting the middle term

    Factoring b2-4b+4

    The first term is, b2 its coefficient is 1.

    The middle term is, - 4b its coefficient is - 4.

    The last term, "the constant", is + 4

    Step-1 : Multiply the coefficient of the first term by the constant 1 • 4 = 4

    Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is - 4.

    -4 + - 1 = - 5 - 2 + - 2 = - 4 That's it

    Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, - 2 and - 2

    b2 - 2b - 2b - 4

    Step-4 : Add up the first 2 terms, pulling out like factors:

    b • (b-2)

    Add up the last 2 terms, pulling out common factors:

    2 • (b-2)

    Step-5 : Add up the four terms of step 4:

    (b-2) • (b-2)

    Which is the desired factorization
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