2x+3y=12 how do I solve for x and y

Question

Padilla

Mathematics

13 July, 20:43

2x+3y=12 how do I solve for x and y

+5

Answers (2)

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Mohamed Douglas · Answer 1

2x + 3y = 12

2x - 2x + 3y = 12 - 2x

3y = 12 - 2x

3 3

y = 4 - 2/3x

2x + 3 (4 - 2/3x) = 12

2x + 12 - 2x = 12

2x - 2x + 12 = 12

0x + 12 = 12

-12 - 12

0x = 0

0 0

x = 0

2 (0) + 3y = 12

0 + 3y = 12

-0 - 0

3y = 12

3 3

y = 4

(x, y) = (0, 4)

Angel Henderson · Answer 2

2x+3y = 12

To solve for the x intercept, y=0

2x+3 (0) = 12

2x = 12

Divide both sides by 2

2x/2x = 12/2x

X = 6

So: (6,0)

To solve for y intercept, x=0

2 (0) + 3y = 12

3y = 12

Divide both sides by 3

3y/3y = 12/3

Y = 4

So: (0,4)