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Padilla
Mathematics
13 July, 20:43
2x+3y=12 how do I solve for x and y
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Mohamed Douglas
13 July, 20:45
0
2x + 3y = 12
2x - 2x + 3y = 12 - 2x
3y = 12 - 2x
3 3
y = 4 - 2/3x
2x + 3 (4 - 2/3x) = 12
2x + 12 - 2x = 12
2x - 2x + 12 = 12
0x + 12 = 12
-12 - 12
0x = 0
0 0
x = 0
2 (0) + 3y = 12
0 + 3y = 12
-0 - 0
3y = 12
3 3
y = 4
(x, y) = (0, 4)
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Angel Henderson
13 July, 20:47
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2x+3y = 12
To solve for the x intercept, y=0
2x+3 (0) = 12
2x = 12
Divide both sides by 2
2x/2x = 12/2x
X = 6
So: (6,0)
To solve for y intercept, x=0
2 (0) + 3y = 12
3y = 12
Divide both sides by 3
3y/3y = 12/3
Y = 4
So: (0,4)
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