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13 July, 20:43

2x+3y=12 how do I solve for x and y

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Answers (2)
  1. 13 July, 20:45
    0
    2x + 3y = 12

    2x - 2x + 3y = 12 - 2x

    3y = 12 - 2x

    3 3

    y = 4 - 2/3x

    2x + 3 (4 - 2/3x) = 12

    2x + 12 - 2x = 12

    2x - 2x + 12 = 12

    0x + 12 = 12

    -12 - 12

    0x = 0

    0 0

    x = 0

    2 (0) + 3y = 12

    0 + 3y = 12

    -0 - 0

    3y = 12

    3 3

    y = 4

    (x, y) = (0, 4)
  2. 13 July, 20:47
    0
    2x+3y = 12

    To solve for the x intercept, y=0

    2x+3 (0) = 12

    2x = 12

    Divide both sides by 2

    2x/2x = 12/2x

    X = 6

    So: (6,0)

    To solve for y intercept, x=0

    2 (0) + 3y = 12

    3y = 12

    Divide both sides by 3

    3y/3y = 12/3

    Y = 4

    So: (0,4)
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