Find the value of n such that x2-10x+n is a perfect square trinomial.

A. - 5

B. 50

C. 100

D. 25

The answer is the last option (Option D), which is:

D. 25

The explanation is shown below:

1. You have that:

(a ± b) ^2=a^2 ± 2ab + b^2

2. The expression given in the problem is:

x^2-10x+n

Where x^2=a and 2ab=10x

2b=10

b=10/2

b=5

3. Therefore, you have:

b^2=5

b^2=25

b^2=n

n=25