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Clayton Robbins
Mathematics
15 May, 07:12
A^2-a+12=0 I need the roots
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Kaitlin Velez
15 May, 07:27
0
a = 1/2 (1 ±sqrt (47))
Step-by-step explanation:
a^2-a+12=0
We will complete the square
Subtract 12 from each side
a^2-a+12-12=0-12
a^2-a=-12
The coefficient of a = - 1
-Divide by 2 and then square it
(-1/2) ^2 = 1/4
Add it to each side
a^2 - a + 1/4=-12 + 1/4
(a-1/2) ^2 = - 11 3/4
(a-1/2) ^2 = - 47/4
Take the square root of each side
sqrt ((a-1/2) ^2) = sqrt (-47/4)
a-1/2 = ±i sqrt (1/4) sqrt (47)
a-1/2 = ±i/2 sqrt (47)
Add 1/2 to each side
a-1/2+1/2 = 1/2± i/2 sqrt (47)
a = 1/2± i/2 sqrt (47)
a = 1/2 (1 ±sqrt (47))
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