ABC has vertices st A (11,6), B (5,6), and C (5,17)

Question

Terrance Irwin

Mathematics

26 November, 16:21

ABC has vertices st A (11,6), B (5,6), and C (5,17)

+1

Answers (1)

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Kale Summers · Answer 1

Distance = ((x2-x1) ^2 + (y2-y1) ^2) ^0.5

Solving

∆ABC A (11, 6),

B (5, 6), and C (5, 17)

AB = 6 units BC = 11 units AC = 12.53 units

∆XYZ X (-10, 5), Y (-12, - 2), and Z (-4, 15)

XY = 7.14 units YZ = 18.79 units XZ = 11.66 units

∆MNO M (-9, - 4), N (-3, - 4), and O (-3, - 15).