Han and Clare walk towards each other a constant rate, meet up, and then continue past each other in opposite direction. We will call the position where they meet up 0 feet and the time when they meet up 0 seconds - Han's velocity is 4 feet per second. - Clare's velocity is - 5 feet per second. - where is each person 10 second before they meet up? - where is each person at the position - 10 feet from the meeting place?

Question

Dominick

Mathematics

16 September, 01:17

Han and Clare walk towards each other a constant rate, meet up, and then continue past each other in opposite direction. We will call the position where they meet up 0 feet and the time when they meet up 0 seconds - Han's velocity is 4 feet per second. - Clare's velocity is - 5 feet per second. - where is each person 10 second before they meet up? - where is each person at the position - 10 feet from the meeting place?

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Answers (1)

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Kenyon Peck · Answer 1

We can find the distance that they are at at 10 seconds by multiplying their velocity.

Han - 40 feet away from Clare.

Clare - - 50 feet away from Han.

Han and Clare would be - 10 feet away from the meeting place at - 10 feet.