Ask Question
28 January, 01:37

From a group of 8 men and 7 women, a committee consisting of 4 men and 5 women is to be formed. A group of 3 men refuses to serve together (each in this group won't serve with either one or both others).

How many different committees are possible?

a. none of the answers provided here

b. 735

c. 4785

d. 105

e. 1365

+4
Answers (1)
  1. 28 January, 01:45
    0
    Answer: Option E.

    Step-by-step explanation:

    The total number of committees possible if no conditions persists is=

    ⁸C₄ x ⁷C₅ = 70 x 21 = 1470

    Now, 3 men refuse to serve together

    So, combination possible for the scenario when they serve together is = ⁵C₄ x ⁷C₅ = 5 x 21 = 105

    So, combination possible for the scenario when they don't servce together is = 1470 - 105 = 1365
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “From a group of 8 men and 7 women, a committee consisting of 4 men and 5 women is to be formed. A group of 3 men refuses to serve together ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers