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29 November, 13:19

Jared wanted to find three consecutive even integers whose sum was 4 times the first of those integers. He let k represent the first integer, then wrote and solved this equation: k + (k+1) + (k+2) = 4k. Did he get the correct answer? Explain

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  1. 29 November, 13:26
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    No, since the question is asking for even integers

    It should look like this, k + (k+2) + (k+4) = 4k
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