Ask Question
29 March, 23:31

Pratap Puri rowed 14 miles down a river in 2 hours, but the return trip took him 3 and one half hours. Find the rate Pratap can row in still water and find the rate of the current. Let x equals rate Pratap can row in still water and y equals rate of the current. What is the rate that Pratap rows in still water?

+1
Answers (1)
  1. 29 March, 23:37
    0
    Let the rate in still water be x and rate of the current be y.

    speed down the river is:

    speed=distance/time

    speed=14/2=7 mi/h

    speed up the river is:

    speed = (14) / (3.5) = 4 mi/hr

    thus total speed downstream and upstream will be:

    x+y=7 ... i

    x-y=4 ... ii

    adding the above equations i and ii we get:

    2x=11

    x=5.5 mi/hr

    thus

    y=5-5.5=1.5 mi/r

    thus the speed in still waters is 5.5 mi/hr

    speed of current is 1.5 mi/hr
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Pratap Puri rowed 14 miles down a river in 2 hours, but the return trip took him 3 and one half hours. Find the rate Pratap can row in ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers