Solve the system of equations

2x+3y=1

y=3x+15

(___,___)

2x + 3y = 1

y = 3x + 15

Get the same variables on each side

3y = 1 - 2x

y = 15 + 3x

Multiply both sides of that second equation by 3 so we can subtract.

3y = 1 - 2x

3y = 45 + 9x

Subtract the equations from each other.

0 = - 44 - 11x

Solve.

44 = - 11x

-4 = x

Use x in an earlier equation to find y.

y = 3x + 15

y = 3 * - 4 + 15

y = - 12 + 15

y = 3

x = - 4, y = 3

{2x+3y=1

{y=3x+15

2x+3 (3x+15) = 1

2x+9x+45=1

11x=-44

x=-4

y=3 * (-4) + 15

y=-12+15=3

y=3

The answer (-4; 3)