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4 December, 17:05

F (x) = 2/x, g (x) = |x| - 1

What is the domain of (fog) (x) ?

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  1. 4 December, 17:18
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    x≠-1,1

    Step-by-step explanation:

    f (g (x)) is a composition where g (x) is is substituted for x in f (x).

    Recall, f (x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

    |x|-1=0

    |x|=1

    x=1,-1
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