What kind of solution (s) does ax^2-bx+c=0 have if b^2-4ac<0?

a. two real solutions

b. one real solution

c. one complex solution

d. two complex solutions

Liike the other user said

when the discriminant is less than 0, you get 2 complex roots

D is the answer

The discriminant is the value that is b^2 - 4ac.

When this number is <0 there will be 2 complex solutions. Letter D.

You would be taking the sqrt of a negative number resulting in a

" + - i sqrt of a number"