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Find the equation of the line through A (4,12) and c (16,16)

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  1. 7 July, 08:43
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    Step-by-step explanation:

    m = y2 - y1 / x2 - x1

    = 16 - 12 / 16 - 4

    = 4/12 = 1/3

    formula = y - y1 = m2 (x - x1)

    y - 12 = 1/3 (x - 4)

    y - 12 = 1x/3 - 4/3

    y = 1x / 3 - 4/3+12

    = 1x/3 + 32 / 3

    y = 1x/3 + 32/3
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