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Adrien Duran
Mathematics
27 June, 06:28
Solving system by substitution x=3y+11, 2x-3y=16
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Arnav Baird
27 June, 06:30
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1. You plug the x equation in the nest on. 2 (3y+11) - 3y=16.
2. You then simplify it. 6y+22-3y=16
3. You simplify it more. 3y+22=16.
4. Next you subtract 22 from each side. 3y=-6.
5. Divide both sides by 3. y=-2
6. Then substitute y for the first equation. x=3 (-2) + 11
7. Next you simplify. x=-6+11
8. Simplify more. x=5
9. You get your results. x=5 and y=-2
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Joyce Kim
27 June, 06:52
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Input 3y+11 for x
2 (3y+11) - 3y=16
6y+22-3y=16
3y = - 6
Divide by 3 to isolate y
y=-2
Now for x ...
x=3 (-2) + 11
=-6+11
=5
x=5
Coordinates (5,-2)
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