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12 March, 18:58

38 = 5 (2-3) + 3b+1

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Answers (2)
  1. 12 March, 19:07
    0
    B=4

    Step-by-step explanation:

    One solution was found:

    b = 4

    Rearrange:

    Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation:

    38 - (5 * (2*b-3) + 3*b+1) = 0

    Step by step solution:

    Step 1:

    Equation at the end of step 1:

    38 - ((5 • (2b - 3) + 3b) + 1) = 0

    Step 2:

    Step 3:

    Pulling out like terms:

    3.1 Pull out like factors:

    52 - 13b = - 13 • (b - 4)

    Equation at the end of step 3:

    -13 • (b - 4) = 0

    Step 4:

    Equations which are never true:

    4.1 Solve : - 13 = 0

    Solving a Single Variable Equation:

    4.2 Solve : b-4 = 0

    Add 4 to both sides of the equation:

    b = 4

    One solution was found:

    b = 4
  2. 12 March, 19:20
    0
    b = 14

    Step-by-step explanation:

    I'm assuming we're solving for b so here it goes!

    38 = 5 (2-3) + 3b+1

    38 = 5 (-1) + 3b+1

    38 = - 5 + 3b+1

    38 = - 4 + 3b

    38 + 4 = - 4 + 4 + 3b

    42 = 3b

    42/3 = 3/b

    14 = b

    b = 14

    Let me know if you have anymore questions! : )
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