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15 June, 12:19

Find 4 consecutive odd integers whose sum is 232

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  1. 15 June, 12:47
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    4 consecutive odd integers ...

    x, x + 2, x + 4, x + 6

    (x) + (x + 2) + (x + 4) + (x + 6) = 232

    4x + 12 = 232

    4x = 232 - 12

    4x = 220

    x = 220/4

    x = 55

    x + 2 = 55 + 2 = 57

    x + 4 = 55 + 4 = 59

    x + 6 = 55 + 6 = 61

    so ur numbers are : 55, 57, 59, 61
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