At a concession stand one person purchased 3 drinks and 3 soft pretzels for a total of $9.00 another person purchased 4 drinks an 2 soft pretzels for a total of $8.50 what is the price of one drink

d=drinks

p=pretzels

1st eq. 3d+3p=9.00

2nd eq. 4d+2p=8.50

multiply 1st eq by 2

6d+6p=18.00

multiply 2nd eq by 3

12d+6p=25.50

subtract

-6d=-7.50

d=1.25

3p=9.00-3d

3p=9-3.75

3p=5.25

p=1.75

price of a pretzel=$1.75

price of a drink = $1.25