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21 January, 00:01

3x^2 - 16x + 2 = 0

Part A: Describe the solution (s) to the equation by just determining the radicand.

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  1. 21 January, 00:26
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    A = 3 b = - 16 and c = 2

    the radicand would be

    sq root (b^2 - 4*a*c) =

    sq root (256 - 4*3*2) =

    sq root (232)

    So the roots will be real and not complex.
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