The length of a rectangle is 2 more than three times the width. The area of the rectangle is 161 square inches. What are the dimensions of the rectangle?

If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?

2x^2 + 3x - 161 = 0

3x^2 + 2x - 161 = 0

6x^2 - 161 = 0

Question

26 December, 02:27

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Answers (1)

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Camryn Osborn · Answer 1

Here is the explanation:

A = L*W

L = 2+3W

161 = (2+3W) * (W)

=2W+2W^2 3W^2+2W-161