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Stephen buys a bag of cookies that contains 9 chocolate chip cookies, 7 peanut butter

cookies, 6 sugar cookies and 7 oatmeal cookies. What is the probability that Stephen

randomly selects a sugar cookie from the bag, eats it, then randomly selects a peanut

butter cookie? Express you answer as a reduced fraction.

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  1. Today, 05:58
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    The probability that Stephen randomly selects a sugar cookie from the bag and eats it, then randomly selects a peanut butter cookie is 3/58 (or) 0.052

    Step-by-step explanation:

    The bag of cookies contain 9 chocolate chip cookies, 7 peanut butter

    cookies, 6 sugar cookies and 7 oatmeal cookies.

    The total number of cookies in the bag = 9+7+6+7 = 29 cookies.

    It is given that, Stephen randomly selects a sugar cookie from the bag and eats it.

    The probability to select a sugar cookie = No. of sugar cookies / total

    ⇒ 6/29

    After that, he randomly selects a peanut butter cookie. We know that the bag now contains 1 cookie less than the total cookies because Stephen ate one sugar cookie.

    Therefore, the total number of cookies in the bag = 28 cookies.

    Probability to select a peanut butter cookie = No. of peanut cookies / total

    ⇒ 7/28

    ⇒ 1/4

    The total probability = P (sugar cookie) * P (peanut cookie)

    ⇒ (6/29) * (1/4)

    ⇒ 6/116

    ⇒ 3/58 (or) 0.052
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