The sum of three different positive integers is 12. show that one of them must be greater than 4.

Question

Delaney Schmidt

Mathematics

15 May, 23:08

The sum of three different positive integers is 12. show that one of them must be greater than 4.

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Answers (2)

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Andy Mays · Answer 1

Let n = 1st positive interger

n+1 = 2nd

n + 2 = 3rd

n+n+1+n+2 = 12

3n + 3 = 12

Minus 3 from 3 and 12

3n = 9

Divide 3n and 9 by 3

n = 3

So, the three intergers are 3, 4, and 5.

Adrienne Pugh · Answer 2

If one is 4, then other may be 3 and so other 2 ... this will get you only 9.

so it is understood that one must be greater than 4