How do I solve the equation, I think I have to use substitution but I am not sure y=3x+11 5x+3y=-44

(-11/2,-11/2)

Step-by-step explanation:

In equation form:

x = - 11/2

y = - 11/2

x=-11/2

y=-11/2

Step-by-step explanation:

Given equations are

y=3x+11 eq (1)

and 5x+3y=-44 eq (2)

Subtitute eq (1) into eq (2) we get

5x+3 (3x+11) = -44

5x+9x+33=-44

14x+33=-44

Adding - 33 to both sides of equation we get

14x+33-33=-44-33

14x+0=-77

14x=-77

Multiplying by 1/14 on both sides of the equation we get

1/14*14x=1/14 (-77)

x=-77/14

x=-11/2

Put the value of x in the eq (1)

y=3 (-11/2) + 11

y=-33/2+11

Taking LCM

y = (-33+22) / 2

y=-11/2.