The following equation has denominators that contain variables. For this equation write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. Keeping the restrictions in mind, solve the equation.

2/x=4/5x+2

x=

Question

Julio Zimmerman

Mathematics

10 September, 06:14

The following equation has denominators that contain variables. For this equation write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. Keeping the restrictions in mind, solve the equation.

2/x=4/5x+2

x=

+4

Answers (1)

Know the Answer?

Prince Chavez · Answer 1

X = 3/5

Step-by-step explanation:

2/x=4/5x+2

Find the LCM of the denominator 5x and 1

2/x = 4/5x + 2/1

2/x = (4 + 10x) / 5x

Cross multiply the equation

2 * 5x = (4 + 10x) * x

10x = 4x + 10x^2

Collect like term of the mixed number

10x - 4x = 10x^2

6x = 10x^2

Divide both side by 2x

6x/2x = {10x^2 } / 2x

3 = 5x

Divide both side by the coefficient of x

3/5 = 5x/5

X = 3/5

The following equation has denominators that contain variables. For this equation write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. Keeping the restrictions in mind, solve the equation.2/x=4/5x+2x=

The following equation has denominators that contain variables. For this equation write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. Keeping the restrictions in mind, solve the equation.

2/x=4/5x+2

x=