How do I solve (4x+1) (x-5) = - 43x-41

Remember you can do anything to an equation as long as you do it to both sides

expand by foiling or distributing

4x²-19x-5=-43x-41

add 43x to both sides and add 41 to both sides

4x²+24x+36=0

factor

facotr out of 4

4 (x²+6x+9) = 0

factor inside

what 2 numbers multiply to get 9 and add to get 6?

3 and 3

4 (x+3) (x+3) = 0

set to 0

x+3=0

x=-3

x=-3 is answer