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Ethen Nolan
Mathematics
21 February, 05:53
Solve for x: x^2 + 14x + 49
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Elise Wilcox
21 February, 06:22
0
Answer: - 7twice
Step-by-step explanation:
This is a question on root of quadratic equation. The interpretation of the question
x² 14x + 49 is
x² + 14x + 49 = 0. meaning that we are to find two possible values for x that will make the expression equal 0.
We can use any of the methods earlier taught. For the purpose of this class, I am using factorization methods
x² + 14x + 49 = 0
Now, find the product of the first and the last terms, is
x² * 49 = 49*²
Now find two terms such that their productbis 49x² and their sum equals 14x, the one in the middle.
We have several factors of 49x² but only one will give sum of 14x. Because of the time, I will only go straight to the required factors.
49x² = 7x * 7x and the sum gives 14x the middle terms ...
Now we now replace the middle one by the factors and then factorize by grouping.
x² + 14x + 49 = 0
x² + 7x + 7x + 49 = 0
x (x + 7) + 7 (x + 7) = 0
(x + 7) (x + 7). = 0
Now to find this value of x,
x + 7 = 0
x. = - 7twice.
The root of the equation = - 7twice.
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