Find the solution to the system of equations: x + 3y = 7

and 2x + 4y = 8

1. Isolate x in the first equation:

2. Substitute the value for x into the second equation:

3. Solve for y

x = 7 - 3y

2 (7 - 3y) + 4y = 8

14 - 6y + 4y = 8

14 - 2y = 8

-2y = - 6

y = 3

x + 3 (3) = 7

4. Substitute y into either original equation:

5. Write the solution as an ordered pair:

Question

Daniel Kemp

Mathematics

21 February, 06:21

Find the solution to the system of equations: x + 3y = 7

and 2x + 4y = 8

1. Isolate x in the first equation:

2. Substitute the value for x into the second equation:

3. Solve for y

x = 7 - 3y

2 (7 - 3y) + 4y = 8

14 - 6y + 4y = 8

14 - 2y = 8

-2y = - 6

y = 3

x + 3 (3) = 7

4. Substitute y into either original equation:

5. Write the solution as an ordered pair:

+3

Answers (1)

Know the Answer?

Paisley Velez · Answer 1

(-2,3)

Step-by-step explanation:

Doing it the way you did and working out the problem you substituted 3 into, x+3 (3) = 7, 3 (3) is 9 and then you subtract 9 from both sides.

7-9=-2

x=-2

Then all you have to do is put it into ordered pairs.

(x, y)

(-2,3)