Find the product of 3a+5 and 2a^ (2) + 4a-2

The answer is 6 a3 + 22 a2 + 14a - 10

My steps:

(3a + 5) (2 a^2 + 4a - 2) = (3a + 5) (2 a^2 + 4a + - 2) = (3a) (2 a^2) + (3a) (4a) + (3a) (-2) + (5) (2 a^2) + (5) (4a) + (5) (-2) = 6 a^3 + 12 a^2 - 6a + 10 a^2 + 20a - 10 = 6 a^3 + 22 a^2 + 14a - 10