2cos^2x = 1

Solve for 0-360 degrees

45,135,315,225

Step-by-step explanation:

2cos^2x = 1

Divide each side by 2

cos^2x = 1/2

Take the square root of each side

sqrt (cos^2 x) = ±sqrt (1/2)

cos x = ±sqrt (1/2)

Make into two separate equations

cos x = sqrt (1/2) cos x = - sqrt (1/2)

Take the inverse cos of each side

cos ^-1 cos (x) = cos ^-1 (sqrt (1/2)) cos ^-1 cos (x) = cos ^-1 (-sqrt (1/2))

x = cos ^-1 (sqrt (1/2)) x = cos ^-1 (-sqrt (1/2))

x = 45 + 360 n x = 135 + 360n

x = 315+360 n x = 225+360n

Between 0 and 360

45,135,315,225

45°, 135°, 225°, 315°

Step-by-step explanation:

2cos²x = 1

cos²x = ½

cosx = + / - 1/sqrt (2)

Basic angle: 45

Since cos has both, positive and negative values, we'll consider all 4 quadrants

45,

180 - 45 = 135

180 + 45 = 225

360 - 45 = 315