2. The formula M=log I/S determines the magnitude of an earthquake, where I is the intensity of the earthquake and S is the intensity of a "standard earthquake." How many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6? Show your work.

Question

Heidy Dunlap

Mathematics

6 October, 01:55

2. The formula M=log I/S determines the magnitude of an earthquake, where I is the intensity of the earthquake and S is the intensity of a "standard earthquake." How many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6? Show your work.

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Answers (1)

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Krish Beard · Answer 1

8 = log I/S

the intensity of the earthquake is 10^8=I/S, so Sx10^8=I

if 6=logI/S, so Sx10^6 = I, so we can write Sx10^8 = Sx10^6x10^2=Ix10^2

an earthquake with a magnitude of 8 is 10² times stronger than an earthquake with a magnitude of 6.