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27 March, 00:53

show that if k is a positive constant, then the area between the x-axis and one arch of the curve y=sin kx is 2/k

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  1. 27 March, 01:21
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    Sin (kx) = 0=>x=0,π, ...

    ∫0πsin (kx) dx=-1/kcos (kx) |π0=-1/k (cos (kπ) - cos (k∗0))

    if k is odd then,=-1/k (-1-1) = - 1/k (-2) = 2/k

    if k is even then,=-1/k (1-1) = 0
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