A box contains 6 red marbles and 4 white marbles. one marble is pulled from the box and not replaced. then a second marble is pulled from the box. what is the probability both marbles are white?

2/15

Step-by-step explanation:

There are 10 marbles in the box

P (1st marble white) = white/total

=4/10 = 2/5

We keep the marble

There are now 9 marbles in the box, 6 red and 3 white

P (2nd marble white no replace) = white / total

= 3/9 = 1/3

P (white, white no replacement) = P (1stwhite) P (2nd white no replace)

= 2/5 * 1/3

= 2/15