The sum of three consecutive intergers is 267. What is the largest integer

90

Step-by-step explanation:

Let the starting number be x, the two consecutive numbers after x is gonna be x+1 and x+2.

If the sum of these three numbers is 267 then:

x + (x+1) + (x+2) = 267

Solve

3x+3=267

3x=267-3

3x=264

x=264/3

x=88

x+1=89

x+2=90

Your three consecutive numbers are 88, 89, and 90.

The largest one of them is 90.

88+89+90=267

Step-by-step explanation:

To do this just divide 267/3 and you get 89, you just look for the previous number (88) and the top number (90) and the sums.

88.89.90