Explain why the inverse of y=3x^2 is not a square root function.

The inverse of the expression will be as follows

y=3x²

We make x the subject

y/3=x²

get the square root of both sides

√ (y/3) = √x²

thus

x=√ (y/3)

replace y by x and x by f^-1 (x), the inverse will be:

f^-1 (x) = √ (y/3)