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27 February, 10:05

Out of 3000 light bulbs that were tested, 126 were defective. find the prbability of defective and non defective

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  1. 27 February, 10:25
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    P (defective) = 126/3000 = 0.042

    P (not defective) = 1 - P (defective)

    = 1 - 0.042 = 0.958
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