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Aidan Stevenson
Mathematics
5 October, 07:48
12x^a y^b / (-6x^a y) ?
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Lawson Meza
5 October, 07:57
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12 / ( - 6) = - 2;
x^a / x^a = 1;
y^b / y = y^ (b - 1);
12x^a y^b / (-6x^a y) = ( - 2) x 1 x y^ (b - 1) = - 2y^ (b - 1);
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