F () = -4 (+2) 2 + 10 in the form f (*) = ax2 + bx+c

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Mathematics

25 May, 02:20

F () = -4 (+2) 2 + 10 in the form f (*) = ax2 + bx+c

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Answers (1)

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King Haley · Answer 1

f (x) = - 4x^2 - 16x - 6.

Step-by-step explanation:

f (*) = - 4 ( * + 2) ^2 + 10

f (x) = - 4 (x^2 + 4x + 4) + 10

f (x) = - 4x^2 - 16x - 16 + 10

f (x) = - 4x^2 - 16x - 6.

F (*) = -4 (*+2) 2 + 10 in the form f (*) = ax2 + bx+c

F () = -4 (+2) 2 + 10 in the form f (*) = ax2 + bx+c