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17 April, 01:15

Suppose S and T are mutually exclusive events. Find P (S or T) ? sp (S) = 6/11 and p (t) = 1/10

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  1. 17 April, 01:43
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    Using P (A∪B) = P (A) + P (B) - P (A∩B)

    If we apply this in the question

    Then P (S∪T) = P (S) + P (T) - P (S∩T)

    = 6/11 + 1/10 - P (S∩T)

    = 71/110 - P (S∩T)

    But events S and T are mutually exclusive events therefore,

    P (S∩T) = 0,

    Hence P (S∪T) = 71/110
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