28 March, 17:25
If 5+20*2^ (2-3x) = 10*2^ (-2x) + 5, what is the value of x?
a - 3
b - 2
28 March, 17:48
Step 1: get rid of the + 5 on both sides.
Step 2: divide by 10 on both sides
Then you have: 2*2^ (2-3x) = 2^ (-2x)
The factor 2 on the left can be brought into the exponent because you're simply multiplying with 2 more ...
2^ (1+2-3x) = 2^ (-2x)
Now you can equate the exponents:
3-3x = - 2x = > 3 = - 2x+3x = > x=3
so d is your answer.
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» If 5+20*2^ (2-3x) = 10*2^ (-2x) + 5, what is the value of x? a - 3 b - 2 c 2 d 3