Find the center of the circle whose equation is x2 - 10x + y2 - 10y = - 1.

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Mathematics

2 June, 05:32

Find the center of the circle whose equation is x2 - 10x + y2 - 10y = - 1.

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Answers (1)

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Deangelo Gonzales · Answer 1

the center of the circle are (5,5)

Step-by-step explanation:

x^2 - 10x + y^2 - 10y = - 1.

x^2 - 10x + (-5) ^2 + y^2 - 10y + (-5) ^2 = - 1 + (-5) ^2 + (-5) ^2

(x-5) ^2 + (y-5) ^2 = - 1 + 25 + 25

(x-5) ^2 + (y-5) ^2 = 49

the center of the circle are (5,5)