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27 January, 14:13

Micheal and Susan have a combined age of 17 years. Micheal is 5 years older than Susan

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Answers (2)
  1. 27 January, 14:34
    0
    Let x be the unknown number which is the age of Susan

    Susan's age: x

    Michael's age: x + 5

    Both total 17 years. The equation would be.

    x + x + 5 = 17

    2x + 5 = 17

    Find x. Transfer 5 to the other side and change its sign

    2x = 17 - 5

    2x = 12

    Find x. Divide both sides by 2.

    2x / 2 = 12 / 2

    x = 6 = > Susan's Age.

    Michael's age: x + 5 = > substitute x by its corresponding value: 6 + 5 = 11.

    To check.

    Susan's Age + Michael's age = 17

    6 + 11 = 17

    17 = 17
  2. 27 January, 14:34
    0
    M+S=17

    M=S+5

    (S+5) + S=17

    2S+5=17

    2S=12

    S=6

    M=11
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