The sequence 28, 34, 40, 46, 52, ..., 88 has 11 terms. Find the sum of the 11 terms.

a) 550

c) 610

Ob) 638

od) 288

Question

Mahoney

Mathematics

24 December, 11:33

The sequence 28, 34, 40, 46, 52, ..., 88 has 11 terms. Find the sum of the 11 terms.

a) 550

c) 610

Ob) 638

od) 288

+4

Answers (2)

Know the Answer?

Karter Cohen · Answer 1

D) 638

Step-by-step explanation:

The pattern shows that they all increase by 6 each time.

The 11 numbers in the pattern would be 28, 34, 40, 46, 52, 58, 64, 70, 76, 82, 88.

Adding all of them together, 28 + 34 + 40 + 46 ... and so on up to 88. This would equal 638.

Chasity Vargas · Answer 2

638

Step-by-step explanation:

28+34+40+46+52+58+64+70+76+82+88 = 638

The sequence 28, 34, 40, 46, 52, ..., 88 has 11 terms. Find the sum of the 11 terms.a) 550c) 610Ob) 638od) 288

The sequence 28, 34, 40, 46, 52, ..., 88 has 11 terms. Find the sum of the 11 terms.

a) 550

c) 610

Ob) 638

od) 288