A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s equals negative 16 t squared plus v 0 ts=-16t2+v0t. Find the time (s) that the projectile will (a) reach a height of 192 ft and (b) return to the ground when v 0v0equals=112 feet per second.

Question

Kelsey Preston

Mathematics

18 December, 20:25

A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s equals negative 16 t squared plus v 0 ts=-16t2+v0t. Find the time (s) that the projectile will (a) reach a height of 192 ft and (b) return to the ground when v 0v0equals=112 feet per second.

+1

Answers (1)

Know the Answer?

Reina · Answer 1

U just need to put value of h=192 feet in equation

h = = - 16t2+v0t

192=-16t^2

here v0=0

now find h

b) when objects reach to ground then h=0

so same equation put v0=112 feet