Subtract seven more than twice a number from the square of one-third of the number to get zero?

Let us assume the unknown number = x

Now we have to follow the details given in the question to bring out the actual equation. In this case there will be only one equation.

(x/3) ^2 - (2x + 7) = 0

(x/3) ^2 = 2x + 7

x^2/9 = 2x + 7

x^2 = 9 (2x + 7)

x^2 = 18x + 63

x^2 - 18x = 63

This would be the final equation for the given problem. his problem needs any solver to understand the words very minutely.