Chloe and Charlie are taking a trip to the pet store to purchase some items for their new puppy they know that they need a bag of food that cost $7 and they also want toys that are $2 each. If chloe has 30$ and her friends has 1/3 of the amounts what is the maximum number of toy they can get

Question

Frankie Chase

Mathematics

18 March, 05:19

Chloe and Charlie are taking a trip to the pet store to purchase some items for their new puppy they know that they need a bag of food that cost $7 and they also want toys that are $2 each. If chloe has 30$ and her friends has 1/3 of the amounts what is the maximum number of toy they can get

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Answers (1)

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Anabel · Answer 1

Answer: the maximum number of toy they can get is 16.

Step-by-step explanation:

If chloe has $30 and her friend has 1/3 of the amount, it means that the amount that her friend has is

1/3 * 30 = $10

The total amount that they have is

30 + 10 = $40

They need a bag of food that cost $7 and they also want toys that are $2 each.

Let x represent the number of toys that they want to get. The total cost of a bag of food and x toys is

7 + 2x

Since they have $40, then the expression would be

7 + 2x ≤ 40

2x ≤ 40 - 7

2x ≤ 33

x ≤ 33/2

x ≤ 16.5

Since the number of toys cannot be a fraction, then the maximum number of toy they can get is 16