The standard form of the equation of a parabola is x=y^2+10y+22 what is the vertex for of the equation

Complete the square of y^2 + 10y to answer this question.

x=y^2 + 10y + 22 becomes x = y^2 + 10y + 100 - 100 + 22, or

x = (y+10) ^2 - 78

Comparing this result to the generic form x = a (y-k) ^2 + h, we see that

h = - 78 and k = - 10.

Then the vertex of this parabola is at (-78, - 10).