Solve the system using elimination. 5 x + 4 y = 12 3 x - 3 y = 18

x = 4, y = - 2

Step-by-step explanation:

Solve the following system:

{5 x + 4 y = 12 | (equation 1)

3 x - 3 y = 18 | (equation 2)

Subtract 3/5 * (equation 1) from equation 2:

{5 x + 4 y = 12 | (equation 1)

0 x - (27 y) / 5 = 54/5 | (equation 2)

Multiply equation 2 by 5/27:

{5 x + 4 y = 12 | (equation 1)

0 x - y = 2 | (equation 2)

Multiply equation 2 by - 1:

{5 x + 4 y = 12 | (equation 1)

0 x+y = - 2 | (equation 2)

Subtract 4 * (equation 2) from equation 1:

{5 x+0 y = 20 | (equation 1)

0 x+y = - 2 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 4 | (equation 1)

0 x+y = - 2 | (equation 2)

Collect results:

Answer: {x = 4, y = - 2