Find the solution to the system of equations, x + 3y = 7 and 2x + 4y = 8.

1. Isolate x in the first equation: x = 7 - 3y2.

Substitute the value for x into the second equation: 2 (7 - 3y) + 4y = 83.

Solve for y: 14 - 6y + 4y = 814 - 2y = 8-2y = - 6y = 34.

Substitute y into either original equation:x =

7 - 3 (3) 5.

Write the solution as an ordered pair: (,)

Question

Noble

Mathematics

29 December, 02:17

Find the solution to the system of equations, x + 3y = 7 and 2x + 4y = 8.

1. Isolate x in the first equation: x = 7 - 3y2.

Substitute the value for x into the second equation: 2 (7 - 3y) + 4y = 83.

Solve for y: 14 - 6y + 4y = 814 - 2y = 8-2y = - 6y = 34.

Substitute y into either original equation:x =

7 - 3 (3) 5.

Write the solution as an ordered pair: (,)

+3

Answers (1)

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Nadia · Answer 1

Hello:

x + 3y = 7 ... (1)

2x + 4y = 8 ... (2)

by (1) : x = 7-3y

Substitute in (2) : 2 (7-3y) + 4y = 8

14-6y + 4y = 8

-2y = - 6

y = 3

x = 7-3 (3)

x = - 2

Write the solution as an ordered pair: (-2,3)