Find the x-intercept of the parabola with vertex (4 - 1) and y-intercept (0 15)

Equation of the parabola in vertex form is y = (x - 4) ^2 - 1

y = x^2 - 8x + 16 - 1

y = x^2 - 8x + 15

The x-intercepts are the values of x when y = 0.

x^2 - 8x + 15 = 0

(x - 3) (x - 5) = 0

x = 3 and x = 5

Therefore, x-intecepts are 3 and 5.