Which is equivalent to (9 y squared minus 4 x) (9 y squared + 4 x), and what type of special product is it? 81 y Superscript 4 Baseline minus 16 x squared, a perfect square trinomial 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares 81 y Superscript 4 Baseline minus 72 x y squared minus 16 x squared, a perfect square trinomial 81 y Superscript 4 Baseline minus 72 x y squared minus 16 x squared, the difference of squares

Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.

Step-by-step explanation:

We need to solve:

(9y^2 - 4x) (9y^2+4x)

Finding the product:

9y^2 (9y^2+4x) - 4x (9y^2+4x)

81y^4+36y^2x-36y^2x-16x^2

81y^4 - 16x^2

Type of Special product

The product is differences of square because

81y^4 = (9y^2) ^2

and 16x^2 = (4x) ^2

So, 81y^4 - 16x^2 = (9y^2) ^2 - (4x) ^2

Hence Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.